Respuesta :
Answer:
The molar concentration of Fe²⁺ in the original solution is 1.33 molar
Explanation:
Moles of K₂Cr₂O₇ = Molarity x Volume (lit)
= 0.025 x 35.5 x 10⁻³
= 0.0008875
Cr₂O₇²⁻ + 6 Fe²⁺ + 14 H⁺ → 2 Cr³⁺ + 6 Fe³⁺ + 7 H₂O
From equation
1 mole K₂Cr₂O₇ used for the oxidation of 6 moles Fe²
0.0008875 mole K₂Cr₂O₇ used for the oxidation of =[tex]\frac{6 X 0.0008875}{1}[/tex] = 0.005325 mole of Fe²
Molarity = [tex]\frac{No. of moles of solute}{Volume of solution(lit)}[/tex]
Molar concentration of Fe² = [tex]\frac{0.005325 X 1000}{25}[/tex] = 1.33 molar
So molar concentration of Fe²⁺ in the original solution = 1.33 molar
