Respuesta :
Answer:
[tex] p \sim N (p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And the parameters are given by:
The mean is given by:
[tex] \mu_p = 0.25[/tex]
The standard deviation is:
[tex]\sigma_{p} =\sqrt{\frac{0.25(1-0.25)}{100}}= 0.0433[/tex]
And the distribution would be bell shaped and normal
Step-by-step explanation:
For this case we have the following info given :
p =0.25 represent the proportion of BYU-Idaho students that are married
n = 100 represent the sample size
And for this case we can check the conditions in order to use the normal distribution:
1) np = 100*0.25 = 25>10
2) n(1-p) =100*(1-0.25)= 75>10[/tex]
3) Independence is assumed in each sample and the probability is the same
So then we have all the conditions satisfied, and the distribution for the proportion would be given by:
[tex] p \sim N (p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And the parameters are given by:
The mean is given by:
[tex] \mu_p = 0.25[/tex]
The standard deviation is:
[tex]\sigma_{p} =\sqrt{\frac{0.25(1-0.25)}{100}}= 0.0433[/tex]
And the distribution would be bell shaped and normal
