(a) The product of [tex](2x-4)\ and\ (3x^2-x+4)[/tex] is calculated to be [tex]=6x^3-14x^2+12x-16[/tex]
(b)The product of [tex](2x-4) \ and\ (3x^2-x+4)\[/tex] is not equal to the product of [tex](4x-2)\ and\ (3x^2-x+4)[/tex]
Step-by-step explanation:
(a)
[tex](2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16[/tex]
b)
[tex](4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8[/tex]
The product of [tex](2x-4) \ and\ (3x^2-x+4)\[/tex] is not equal to the product of [tex](4x-2)\ and\ (3x^2-x+4)[/tex]
