Answer:
[tex]\Delta v=-0.952m^3/kg[/tex]
[tex]\Delta h=0[/tex]
Explanation:
In this case, since neon could be considered as an ideal gas, the specific volumes at the first and second state are respectively:
[tex]v_1=\frac{Rg*T_1}{p_1}=\frac{0.4119kJ/kg*K*289.15}{100kPa} =1.19m^3/kg\\[/tex]
[tex]v_2=\frac{Rg*T_2}{p_2}=\frac{0.4119kJ/kg*K*289.15}{500kPa} =0.238m^3/kg\\[/tex]
Thus, the change in the specific volume turns out:
[tex]\Delta v=v_2-v_1=0.238m^3/kg-1.19m^3/kg\\\Delta v=-0.952m^3/kg[/tex]
Which value has sense for the compression.
In addition, the specific enthalpy change just depend on the temperature as it is an ideal gas, therefore, since the process es isothermic:
[tex]\Delta h=Cp\Delta T=0[/tex]
Best regards.
