The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
Explanation:
Given:
Two rectangles are proportional.
Length and width of 1 rectangle = 6 : 8
Dimensions of the other rectangle = ?
Let length and width of the other rectangle be x : y
According to the question:
[tex]\frac{6}{8} :\frac{x}{y}[/tex]
[tex]\frac{6}{8} X \frac{y}{x}[/tex]
So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
