0.147 liters is the volume of the balloon in the liquid nitrogen.
Explanation:
Pressure of helium gas P1 = 1 atm
temperature T1 = 20 degrees or 293.15 K
volume V1 = 2.91 L
Pressure when immersed in liquid nitrogen = 5.20 atm
temperature T2 = -196 degrees 77.15 K
V2 = ?
Gas law for expansion of gases:
[tex]\frac{P1V1}{T1}[/tex] = [tex]\frac{P2V2}{T2}[/tex]
V2 = [tex]\frac{P1V1T2}{T1P2}[/tex] equation 1
Putting the values in the equation:
V2 = [tex]\frac{1 X 2.91 X 77.15}{293.15 X 5.20}[/tex]
= 0.147 Litre is the volume of the balloon immersed in liquid nitrogen.
hence V2 = 0.147 litres.
