contestada

You pull on a spring whose spring constant is 20 N/m, and stretch it from its equilibrium length of 0.4 m to a length of 0.9 m. Estimate the work done by dividing the stretching process into two stages and using the average force you exert to calculate work done during each stage. J

Respuesta :

Answer:

W= 6.5 J      

Explanation:

Given that

Spring constant ,K= 20 N/m

Initial length ,x₁ = 0.4 m

Final length , x₂ = 0.9 m

The work done is given as follows

[tex]W=\dfrac{1}{2}K(x_2^2-x_1^2)[/tex]

Now by putting the values in the above equation

[tex]W=\dfrac{1}{2}\times 20\times (0.9^2-0.4^2)\ J[/tex]

W= 6.5 J

Therefore work done will be 6.5 J.

Otras preguntas