Answer:
Length of Brace = [tex]x=\sqrt{5}h[/tex]
Step-by-step explanation:
The height is "h"
The width is 2 times that, so
Width is "2h"
The length of the brace is the diagonal from one corner to another. This length can be solved using pythagorean theorem, which will say:
Length^2 + Width^2 = length^2 [where length is length of brace, what we want]
Thus,
[tex](h)^2+(2h)^2=x^2[/tex]
Note: Let "x" be the length of brace
Now, simplifying:
[tex](h)^2+(2h)^2=x^2\\h^2+4h^2=x^2\\x^2=5h^2\\x=\sqrt{5h^2}\\x=\sqrt{5}h[/tex]
The expression for length of brace (x) is: [tex]x=\sqrt{5}h[/tex]
