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A point charge q is located at the origin surrounded by a spherical medium with dielectric constant ε and a radius of R. Outside the spherical medium is vacuum. A second point charge q is located at a distance d >> R from the origin. Calculate the Coulomb’s force the second charge experiences

Respuesta :

Answer:

[tex]F =K \frac{q_{1}q_{2} }{(d-R)^{2} }[/tex]

Explanation:

According to Coulomb's law, the force of attraction between two charges, q1 and q2 is directly proportional to the product of the charges and inversely proportional to the distance separating them.

[tex]F =K \frac{q_{1}q_{2} }{d^{2} }[/tex]

Since d > R

the second charge will experience a force [tex]F =K \frac{q_{1}q_{2} }{(d-R)^{2} }[/tex]

Where K = 9.0 x 10⁹ N.m²/C²

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