0.23 moles of a gas will 700 m hold at -100 oC and 86 atm.
Explanation:
given that:
volume = 700 ml OR 0.7 Litre (for converting into litre it is divided with 1000 as 1 litre = 1000ml)
temperature = -100 degrees OR 173.15 K
pressure = 86 atm
R = 0.082057 L atm mol-1K-1
n=?
It is known that when Volume is taken in litres, pressure in atm, and temperature in Kelvin then R= 0.082057 L atm mol-1K-1,
From the formula for ideal gas:
PV = nRT
putting the values in the formula:
n = [tex]\frac{RT}{PV}[/tex]
= [tex]\frac{0.0820507 X 173.15}{0.7 X 86}[/tex]
= 0.23 moles of the gas will be required.
