The equation of the line is [tex]y = (3/5)x + 26/5[/tex]
Step-by-step explanation:
To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.
The equation of the line when a point and slope is given :
⇒ [tex](y-y1) = m(x-x1)[/tex]
where,
Therefore, the equation of the line can be framed by,
⇒ [tex](y-(-4)) = 3/5 (x-2)[/tex]
⇒ [tex](y+4) = 3/5(x-2)[/tex]
Take the denominator 5 to the left side of the equation.
⇒ [tex]5(y+4) = 3(x-2)[/tex]
Now, multiply the number outside the bracket to each term inside the bracket.
⇒ [tex]5y+20 = 3x -6[/tex]
⇒ [tex]5y = 3x-26[/tex]
Divide by 5 on both sides of the equation,
⇒ [tex]y = (3/5)x + 26/5[/tex]
Therefore, the equation of the line is [tex]y = (3/5)x + 26/5[/tex]
Answer:
3x - 5y = 26
Step-by-step explanation:
y = mx + c
y = (3/5)x + c
-4 = (3/5)(2) + c
-4 = 6/5 + c
c = -4 - 6/5
c = -26/5
y = (3/5)x - 26/5
Standard form is:
ax + by = c
y = (3/5)x - 26/5
5y = 3x - 26
3x - 5y = 26
