The component of the weight of the box along the surface is 34.9N.
Explanation:
Given that
Mass of the box m=21kg
Angle of inclination θ=10°
Acceleration due to gravity g=9.8 [tex]m/s^{2}[/tex]
Weight of an object is the force with which the earth attracts the object. Since weight is a force its unit is Newton(N). When an object is placed on a surface that has no inclination, its weight is given by the expression
W=mg
where m denotes mass of the object and g denotes the acceleration due to gravity.
When the surface has an inclination, the weight of the object can be resolved into two components that are parallel and perpendicular to the surface.
The component of weight parallel to the surface is given by
W=mgsinθ
where θ is the angle of inclination
The component of weight perpendicular to the surface is given by
W=mgcosθ
In the given problem, we have to find out the parallel component of weight
W=mgsinθ
[tex]W=21\times 9.8 \timessin10\°\\=21\times9.8\times0.17\\=34.9N[/tex]
The component of the weight of the box along the surface is 34.9N
