A dart gun consists of a horizontal spring with k = 52 Newtons/m that is compressed 43
the gun is cocked. What is the initial acceleration of a 75-g dart when the gun is fired?

Respuesta :

Answer:

[tex]299 m/s^2[/tex]

Explanation:

When a spring is compressed, the force exerted by the spring is given by:

[tex]F=kx[/tex]

where

k is the spring constant

x is the compression of the spring

In this problem we have:

k = 52 N/m is the spring constant

x = 43 cm = 0.43 m is the compression

Therefore, the force exerted by the spring on the dart is

[tex]F=(52)(0.43)=22.4 N[/tex]

Now we can apply Newton' second law of motion to calculate the acceleration of the dart:

[tex]F=ma[/tex]

where

F = 22.4 N is the force exerted on the dart by the spring

m = 75 g = 0.075 kg is the mass of the dart

a is its acceleration

Solving for a,

[tex]a=\frac{F}{m}=\frac{22.4}{0.075}=299 m/s^2[/tex]