Respuesta :
Answer:
Two zero pair
[tex]f(x)=(2x-3)(x+2)[/tex]
Step-by-step explanation:
We are given the following quadratic equation:
[tex]f(x) = 2x^2+x-6[/tex]
Since, this a quadratic equation we would have two zero pairs for this model.
Factored form of polynomial:
[tex]f(x) = 2x^2+x-6\\f(x)=2x^2+ 4x -3x -6\\f(x)=2x(x+2)-3(x+2)\\f(x)=(2x-3)(x+2)[/tex]
is the required factored form of the given polynomial.
The equivalent that is factored using the expression in the question is given as 3.
How to solve for the equivalent using factoring
The equation is of the form
2x² + x – 6
When factored we have
(2x-3)(x+2)
The equation can be rewritten as 2x²- 3x+4x-6
The factored form is 3((2x-3)(x+2)
Read more on polynomials here: https://brainly.com/question/2833285
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