Answer:
Molarity of sulphuric acid solution = 0.76 (M)
Explanation:
At first we calculate moles of reacted aluminium hydroxide =[tex]\frac{0.875}{Molecular mass}[/tex]
= [tex]\frac{0.875}{78}[/tex]
= 0.011
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
Since 2 mole react with 3 mole H₂SO₄
0.011 mole react with = [tex]\frac{3}{2}[/tex] x 0.011
= 0.016 mole
Molarity of H₂SO₄ = [tex]\frac{number of mole}{Volume of solutio}[/tex] = [tex]\frac{0.016 X 1000}{22}[/tex] = 0.76 (M)
