Answer:
Equilibrium concentration of Cl₂ = 0.013 molar
Equilibrium concentration of Cl = 0.0072 molar
Explanation:
Cl ₂ ( g ) ⇄ 2 Cl ( g )
No. of moles of Cl₂(g) = [tex]\frac{Mass given}{Molar mass}[/tex]
= [tex]\frac{3.45}{71}[/tex]
= 0.048 mole
Concentration of Cl₂ = [tex]\frac{0.048 }{3.5}[/tex] M = 0.013 molar
From the above equation we get
[tex]K_{c}[/tex] = [tex]\frac{[Cl]^{2} }{[Cl_{2} ]}[/tex]
[Cl]² = Kc X [Cl₂]
= 0.00376 x 0.013
= 5.22 x 10⁻⁵ molar
[Cl] = 0.0072 molar
