The answer for the following question is answered below
Explanation:
Given:
mass of zinc nitrate = 30 grams
[tex]Zn +2 HNO_{3}[/tex] → [tex]Zn(NO_{3} ){2}[/tex] + [tex]H_{2}[/tex]
2×53 189
molar mass of nitric acid is 53 grams
molar mass of zinc nitrate is 189 grams
2×53 → 189
? → 30
(i.e.) = ( 2×53 × 30) ÷ 189
= 16.8 grams
16.8 grams of nitric acid is needed to produce 30 grams of zinc nitrate
