A 0.80 kg object tied to the end of a 2.0 m string swings as a pendulum. At the lowest point of its swing, the object has a kinetic energy of 10 J. Determine the speed of the object at the instant when the string makes an angle of 50o with the vertical.

Respuesta :

Answer:

3.32 m/s

Explanation:

From the law of conservation of energy, the sum of mechanical and kinetic energy should be equal to the 10 J given. Potential energy is given by mgh where m is mass, g is acceleration due to gravity and h is the height. For this case, [tex]h= l(1-cos\theta)[/tex] and l is string length, given as 2 m, \theta is given as 50 degrees. Kinetic energy is given by [tex]0.5mv^{2}[/tex] and it is this velocity that is unknown.

[tex]10J=0.5\times 0.8kg\times v^{2}+ 0.8kg\times 9.81\times 2m(1-cos 50^{\circ})\\v\approx 3.32 m/s[/tex]

The speed of the object will be "3.32 m/s".

Given,

  • Mass, m = 0.80 kg
  • Length, L = 2 m
  • Kinetic energy, K.E = 10 J
  • Angle, θ = 50

The height of the pendulum will be:

→ [tex]h = L(1- Cos \Theta)[/tex]

By putting the values, we get

      [tex]= 2(1 - Cos\ 50)[/tex]

      [tex]= 0.7144 \ m[/tex]

By using the conservation of energy, we get

→ [tex]10 = \frac{1}{2} mv^2 +mgh[/tex]

  [tex]10 = \frac{1}{2} (0.8)v^2+0.8\times 9.8\times 0.7144[/tex]

   [tex]v = 3.32 \ m/s[/tex]

Thus the response above is right.

Learn more about angle here:

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