Answer:
2.93181 Kj
Explanation:
Given data:
Mass of mercury = 345 g
Initial temperature = 72.7°C
Final temperature = 12.0°C
Heat released = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of mercury = 0.14 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
ΔT = 12.0°C - 72.7°C
ΔT = -60.7°C
Q = m.c. ΔT
Q = 345 g × 0.14 j/g.°C × -60.7°C
Q = -2931.81 j
Joule to Kj conversion:
2931.81 j × 1 kj /1000 j = 2.93181 Kj
