Answer: The equilibrium concentration of chloride ions in the solution is 4.532 M
Explanation:
We are given:
Initial molarity of [tex][CoCl_2.6H_2O][/tex] = 0.054 M
Initial molarity of HCl = 4.60 M
Equilibrium molarity of [tex][CoCl_4]^{2-}[/tex] = 0.034 M
The chemical equation for the reaction of [tex][CoCl_2.6H_2O][/tex] and HCl follows:
[tex][CoCl_2.6H_2O]+2HCl\rightarrow H_2[CoCl_4]+6H_2O[/tex]
Or,
[tex][CoCl_2.6H_2O]+2Cl^-\rightarrow [CoCl_4]^{2-}+6H_2O[/tex]
Initial: 0.054 4.60
At eqllm: 0.054-x 4.60-2x x 6x
Evaluating the value of 'x':
[tex]x=0.034[/tex]
So, equilibrium concentration of [tex]Cl^-[/tex] = (4.60 - 2x) = [4.60 - 2(0.034)] = 4.532 M
Hence, the equilibrium concentration of chloride ions in the solution is 4.532 M