What is the x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5? x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1

Respuesta :

Answer:

x = -2

Step-by-step explanation:

The image and whole question is attached.

The end point are:

J(-6, -2)

K(8, -9)

We need to divide the segment in ratio 2:5

The formula is:

[tex]x=(\frac{m}{m+n})(x_2-x_1)+x_1[/tex]

m and n are the ratio, hence

m = 2

n = 5

x_2 = 8

x_1 = -6

Substituting, we get the x-coordinate:

[tex]x=(\frac{m}{m+n})(x_2-x_1)+x_1\\x=\frac{2}{2+5}(8-(-6))+(-6)\\x=\frac{2}{7}(14)-6\\x=4-6\\x=-2[/tex]

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Answer:

-2

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