Answer:
The motional emf generated between the ends of the wire is
7341 V
Explanation:
Given :
Length of satellite [tex]l = 2.84 \times 10^{4}[/tex] m
Magnetic field [tex]B = 5.16 \times 10^{-5}[/tex] T
Speed of shuttle [tex]v = 5.01 \times 10^{3} \frac{m}{s}[/tex]
The emf generated between the ends of the wire is given by,
Induced emf = [tex]Blv\sin \theta[/tex]
Where [tex]\sin 90 = 1[/tex]
emf = [tex]5.16 \times 10^{-5} \times 5.01 \times 10^{3} \times 2.84 \times 10^{4}[/tex]
emf ≅ [tex]7341[/tex] V
Therefore, the motional emf generated between the ends of the wire is
7341 V
