Answer:
Explanation:
mass of bumper car, m1 = 475 kg
mass of trailing car, m2 = m = 365.4 kg
mass of bumper car = 30% greater than the trailing car
475 = 130 x m / 100
m = 365.4 kg
initial velocity of bumper car, u1 = 3.7 m/s
initial velocity of trailing car, u2 = 7.5 m/s
Let the velocity of the bumper car and the trailing car after collision is v1 and v2 respectively.
Use conservation of momentum
m1 x u1 + m2 x u2 = m1 x v1 + m2 x v2
475 x 3.7 + 365.4 x 7.5 = 475 v1 + 365.4 v2
4498 = 475 v1 + 365.4 v2 .... (1)
As the collision is elastic so the coefficient of restitution is 1.
[tex]e=\frac{v_{2}-v_{1}}{u_{1}-u_{2}}[/tex]
v2 - v1 = 3.7 - 7.5
v1 - v2 = 3.8 ... (2)
from equation (1)
v1 - (4498 - 475 v1) / 365.4 = 3.8
365.4 v1 - 4498 + 475 v1 = 1388.52
840.4 v1 = 5886.52
v1 = 7 m/s
Put in equation (2)
7 - v2 = 3.8
v2 = 3.2 m/s
