Respuesta :
Explanation:
Given that,
Speed of an electron, [tex]v=4.4\times 10^3\ m/s[/tex]
Magnetic field, B = 1.45 T
Magnetic force, [tex]F=1.4\times 10^{-16}\ N[/tex]
The magnetic force is given by in terms of charge, speed and magnetic field on which the charged particle is kept :
[tex]F=qvB\sin\theta\\\\\sin\theta=\dfrac{F}{qvB}\\\\\sin\theta=\dfrac{1.4\times 10^{-16}}{1.6\times 10^{-19}\times 4.4\times 10^3\times 1.45}\\\\\sin\theta=0.137\\\\\theta=7.88^{\circ}[/tex]
or
[tex]\theta=180-7.88=172.12^{\circ}[/tex]
Hence, this is the required solution.
Answer:
Explanation:
Charge on electron, e = - 1.6 x 10^-19 C
Magnetic field, B = 1.45 T
Force, F = 1.4 x 10^-16 N
The formula for the magnetic force is given by
F = q x v x B x Sinθ
Where, θ is the angle between the velocity vector and the magnetic field vector.
1.4 x 10^-16 = - 1.6 x 10^-19 x 4.4 x 10^3 x 1.45 x Sinθ
Sin θ = - 0.1371
θ = 172°
