Respuesta :
Answer:
The work done on the Frisbee is 1.36 J.
Explanation:
Given that,
Mass of Frisbee, m = 115 g = 0.115 kg
Initial speed of Frisbee, u = 12 m/s at a point 1 m above the ground
Final speed of Frisbee , v = 10.9674 m/s when it has reached a height of 2.00 m. Let W is the work done on the Frisbee by its weight. According to work energy theorem, the work done is equal to the change in its kinetic energy. So,
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\W=\dfrac{1}{2}\times0.115\times\left((10.9674)^{2}-(12)^{2})\right)\\\\W=-1.36\ J[/tex]
So, the work done on the Frisbee is 1.36 J. Hence, this is the required solution.
Answer:
Explanation:
mass of frisbee, m = 115 g = 0.115 kg
initial height, h = 1 m
final height, h' = 2 m
Work done on frisbee by its weight
W = - mg(h' - h)
W = - 0.115 x 9.8 x ( 2 - 1)
W = - 1.127 J
