Answer:
Percent yield of NaCl = 20.85%
Explanation:
Given data:
Mass of HCl = 30 g
Actual yield of NaCl = 10 g
Percent yield of NaCl = ?
Solution:
Chemical equation:
HCl + NaOH → NaCl + H₂O
Moles of HCl:
Number of moles = mass/ molar mass
Number of moles = 30 g/ 36.5 g/mol
Number of moles = 0.82 mol
Now we will compare the moles of HCl with NaCl
HCl : NaCl
1 : 1
0.82 : 0.82
Theoretical yield:
Mass = number of moles × molar mass
Mass = 0.82 mol × 58.5 g/mol
Mass = 47.97 g
Percentage yield:
Formula:
Percent yield = Actual yield / theoretical yield × 100
Now we will put the values.
Percent yield = 10 g / 47.97 g × 100
Percent yield = 20.85%
