Answer:
The displacement of the spring due to weight is 0.043 m
Explanation:
Given :
Mass [tex]m = 2[/tex] Kg
Spring constant [tex]k = 450 \frac{N}{m}[/tex]
According to the hooke's law,
[tex]F = -kx[/tex]
Where [tex]F =[/tex] force, [tex]x =[/tex] displacement
Here,
[tex]F = mg[/tex] ( [tex]g = 9.8 \frac{m}{s^{2} }[/tex] )
[tex]F = 2 \times 9.8 = 19.6[/tex] N
Now for finding displacement,
[tex]x = \frac{F}{k}[/tex]
Here minus sign only represent the direction so we take magnitude of it.
[tex]x = \frac{19.6}{450}[/tex]
[tex]x = 0.043[/tex] m
Therefore, the displacement of the spring due to weight is 0.043 m
The displacement of the spring due to weight is 0.043m.
This is defined as the straight line distance in a particular direction.
We were given mass as 2kg and spring constant (K) as 450N/m.
Hooke's law states that F = -kx where F is force and x is displacement.
F = mg
= 2 × 9.8 = 19.6N
Displacement (x) = F/ k
= 19.6/450 = 0.043 m.
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