Given:
Width = x
Length = x + 3
To find:
Which model and solution is correct for the given situation.
Solution:
Sum of the length and width of a rectangle is more than 15 units.
⇒ width + length > 15
[tex]\Rightarrow x + x+ 3 >15[/tex] --------------- (1)
This model represents the situation.
Adding x:
[tex]\Rightarrow 2x+ 3>15[/tex]
Subtract 3 on both sides.
[tex]\Rightarrow 2x+ 3-3>15-3[/tex]
[tex]\Rightarrow 2x >12[/tex]
Divide by 2 on both sides.
[tex]$\Rightarrow\frac{ 2x }{2}>\frac{ 12}{2}[/tex]
[tex]$\Rightarrow x>6[/tex] --------------- (2)
The correct model and solution is represents the situation is
[tex]x+x+3>15 ; \text { solution } x>6[/tex].
