A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend who is located at point B.


Which equation represents Grant’s path?


y = 2 – 4x

y = 4 – X over 2

y = 6 – X over 4

y = 8 – 2x

A circle representing a pool is graphed with a center at the origin Grant enters the pool at point A and swims over to a friend who is located at point BWhich e class=

Respuesta :

Answer:

The equation of Grant's path is y = 4 - x over 2 2nd answer

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0)

The formula of the slope of a line is [tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

∵ Grant's path is a line from point A to point B

∴ The equation of AB represents Grant's path

Lets find the slope of AB using the formula of the slope above

∵ A = (8 , 0)

∵ B = (-4 , 6)

∴ [tex]x_{1}[/tex] = 8 and [tex]x_{2}[/tex] = -4

∴ [tex]y_{1}[/tex] = 0 and [tex]y_{2}[/tex] = 6

∵ [tex]m=\frac{6-0}{-4-8}=\frac{6}{-12}[/tex]

∴ [tex]m=-\frac{1}{2}[/tex]

Substitute the value of m in the form of the equation

∵ y = m x  + b

∴ y = [tex]-\frac{1}{2}[/tex] x + b

∵ b is the value of y at x = 0

∵ y = 4 at x = 0 ⇒ from the figure

∴ b = 4

∴ y = [tex]-\frac{1}{2}[/tex] x + 4

We can write [tex]-\frac{1}{2}[/tex] x as [tex]-\frac{x}{2}[/tex]

∴ y =  [tex]-\frac{x}{2}[/tex] + 4

- Switch the two terms of the right hand side

∴ y = 4 -  [tex]\frac{x}{2}[/tex]

The equation of Grant's path is y = 4 -  [tex]\frac{x}{2}[/tex]