The total pressure for a mixture of N2O4 and NO2 is 1.5atm. If Kp = 7.1 at 25°C, calculate the partial pressure of each gas in the mixture. (HINT 1.5 = 2pNO2 + pN2O4) 2NO2 (g) = N2O4 (g)

Respuesta :

Answer:

[tex]N_{2} O_{4}[/tex] : 0.5 atm and [tex]N_{} O_{2}[/tex] : 1 atm

Explanation:

In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.

It is given that [tex]P_{total}[/tex] = 1.5 atm

The mole fraction of each gas can be calculated in the following way:

[tex]N_{2} O_{4}[/tex] = moles of [tex]N_{2} O_{4}[/tex] ÷ total moles present = [tex]\frac{1}{3}[/tex]

[tex]N_{} O_{2}[/tex] = moles of [tex]N_{} O_{2}[/tex] ÷ total moles present = [tex]\frac{2}{3}[/tex]

Partial pressure of [tex]N_{2} O_{4}[/tex] : 1.5 × [tex]\frac{1}{3}[/tex] = 0.5 atm

Partial pressure of [tex]N_{} O_{2}[/tex] : 1.5 × [tex]\frac{2}{3}[/tex] = 1 atm

Hope that answers the question, have a great day!