Answer:
Explanation:
We shall apply Gauss's Law to find the solution .
flux entering the cube = E X A
= 46.8 X 147.1 X 147.1 Weber
flux going out of cube
= 114 x 147.1 X 147.1 Weber
Net flux going out
= ( 114 x 147.1 X 147.1 - 46.8 X 147.1 X 147.1 )
= 1454101.15 weber .
according to Gauss's law
q / ε₀ = 1.4541 x 10⁶ , q is required charge inside the cube.
q = 8.85 x 10⁻¹² x 1.4541 x 10⁶
= 12.868 x 10⁻⁶ C
= 12.868 μC.
Answer:
Explanation:
Electric field at height 241 m , E = 46.8 N/C
Electric field at height 93.1 m, E' = 114 N/C
length of edge, a = 147.1 m
The total flux
Фnet = Ф + Ф'
Фnet = E A Cos 180 + E' A Cos 0
Фnet = A ( E' - E)
According to the Gauss theorem
Фnet = enclosed charge / ∈o
∈o x A (E' - E) = q
q = 8.854 x 10^-12 x 147.1 x 147.1 x (114 - 46.8)
q = 1.29 x 10^-5 C
