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You have determined a GC spectrum for your sample oil. You find 3 peaks. From determination of peak area, you find that the percent compositions represented by the peaks are: peak A is 66 percent , peak B is 22.66 percent, and peak C is 11.33 percent. The M.W. of your diene is 136 g/m. How many grams of Maleic Anhydride (M.W. 98 g/m) will you use to react with your 2.5g sample of crude diene?

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ajeigbeibraheem

Answer:

1.19 g

Explanation:

Given that:

Molecular weight of diene [tex]M.W_d =[/tex]136 g/mol

Molecular weight of Maleic Anhydride [tex]M.W_{m.a}=[/tex]96 g/mol

Mass of crude diene = 2.5 g

Percent of Composition for Peak A = 66%

Percent of Composition for Peak B = 22.66%

Percent of Composition for Peak C = 11.33%

Let us determine the amount of diene in the sample;

So, using [tex]A_d[/tex] to represent the amount of diene; we have :

[tex]A_d[/tex]  = [tex]m*P_a[/tex]

[tex]A_d[/tex]  = [tex]2.5 *\frac{66}{100}[/tex]

[tex]A_d[/tex]  = 1.65 g

Using the limiting reagent equation to determine the amount of Maleic Anhydride [tex]A_{ma}[/tex]

[tex]A_{ma}[/tex] = [tex]A_d[/tex]  [tex]* \frac{1mole diene}{M.W_d} *\frac{M.W_{m.a}}{1 mole of maleic anhydride}[/tex]

[tex]A_{ma}[/tex] = [tex]1.65 * \frac{1 mole}{136}*\frac{98}{1 mole}[/tex]

[tex]A_{ma}[/tex] = 1.19 g

The  grams of Maleic Anhydride used to react with 2.5 g sample of crude diene = 1.19 g

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