Answer:
0.1428 is the probability that both the pirate and the Captain hit each other's ships.
Step-by-step explanation:
We are given the following in the question:
Probability of captain hitting pirate's ship =
[tex]P(C)=\dfrac{1}{2}[/tex]
Probability of pirate hitting captain's ship =
[tex]P(P) = \dfrac{2}{7}[/tex]
If events are independent events, we can write:
[tex]P(A\cap B) =P(A)\times P(B)[/tex]
We have to evaluate the probability that both the pirate and the Captain hit each other's ships.
[tex]P(C\cap P) = P(C) \times P(P)\\\\P(C\cap P) = \dfrac{1}{2}\times \dfrac{2}{7} = \dfrac{1}{7} = 0.1428[/tex]
0.1428 is the probability that both the pirate and the Captain hit each other's ships.
