Answer:
The image will form at distance d = 7.75 cm from the mirror
Explanation:
As we know that the bulb is placed at 15 cm distance from the concave mirror
Then the image will form at distance d = 8.9 cm
now we have
[tex]\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}[/tex]
so we have
[tex]\frac{1}{8.9} + \frac{1}{15} = \frac{1}{f}[/tex]
[tex]f = 5.58 cm[/tex]
Now when bulb is placed at distance 20 cm from the mirror
then again we have
[tex]\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}[/tex]
[tex]\frac{1}{d_i} + \frac{1}{20} = \frac{1}{5.58}[/tex]
now we have
[tex]d_i = 7.75 cm[/tex]