Answer:
The resistance will be twice the original resistance
Explanation:
This is a fairly simple question, the formular for the resistance of a wire is given as
R = rho *length / area
Where R = resistance
Rho = resistivity
L = length
A = area
Since the density and area are constant I.e they do not change
R/ length = rho/ area
The initial length is given as L, when this length is stretched to twice its original length ,it becomes 2×L = 2L
Let x represent the resistance when the length is doubled
R/ L = x / 2L
x = 2LR / L ; dividing by L
We have that x = 2R ; twice the resistance
Answer:
Explanation:
Given:
L2 = 2 × L1
Using the formula,
Resistivity, d = (R × A)/L
Where,
R = resistance
A = area
L = length
1. d1 = (R1 × A1)/L1
2. d2 = (R2 × A2)/L2
Equating both 1 and 2 together,
(R2 × A2)/L2 = (R1 × A1)/L1
(R2 × A2)/(2 × L1) = (R1 × A1)/L1
Assume A1 = A2,
R2 = [(R1 × A1) × 2 × L1]/(A1 × L1)
R2 = 2 × R1
