Answer:
[tex]\large \boxed{\text{133 mL}}[/tex]
Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.
[tex]p_{1}V_{1} = p_{2}V_{2}[/tex]
Data:
[tex]\begin{array}{rcrrcl}p_{1}& =& \text{12.12 atm}\qquad & V_{1} &= & \text{155 mL} \\p_{2}& =& \text{14.14 atm}\qquad & V_{2} &= & ?\\\end{array}[/tex]
Calculations:
[tex]\begin{array}{rcl}12.12 \times 155 & =& 14.14V_{2}\\1879 & = & 14.14V_{2}\\V_{2} & = &\dfrac{1879}{14.14}\\\\& = &\textbf{133 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{133 mL}}[/tex]
