Answer: 0.529 atm
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.998 atm
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 2 L
[tex]V_2[/tex] = final volume of gas = 3.5 L
[tex]T_1[/tex] = initial temperature of gas = [tex]34.0^oC=273+34.0=307.0K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]12.0^oC=273+12.0=285.0K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.998\times 2}{307.0K}=\frac{P_2\times 3.5}{285.0K}[/tex]
[tex]P_2=0.529atm[/tex]
Thus the pressure if it is brought to a higher altitude where it now occupies 3.5 L and is at 12.0 °C is 0.529 atm
