w much
ery day?
14. Jerome bought 1ż pounds of jelly
beans, & pound of gum balls, and
2 pounds of chocolate. How many
total pounds of candy did he buy?
A. 35 pounds
B. 4 pounds
C. 4į pounds
garage. He
ed pulley
Ken have
D.
5 pounds

w much ery day 14 Jerome bought 1ż pounds of jelly beans amp pound of gum balls and 2 pounds of chocolate How many total pounds of candy did he buy A 35 pounds class=

Respuesta :

Jerome bought C. [tex]4\frac{7}{8}[/tex] pounds of candy.

Step-by-step explanation:

Step 1:

First, we must convert the mixed fractions into improper fractions. To do that we multiply the whole number with the denominator and add with it the numerator while the denominator remains the same.

To convert this fraction [tex]1\frac{1}{2} = \frac{(1)(2)+1}{2} =\frac{3}{2} .[/tex]

To convert this fraction [tex]2\frac{3}{4} = \frac{(2)(4)+3}{4} =\frac{11}{4} .[/tex]

So Jerome bought [tex]\frac{3}{2}[/tex] pounds of jelly beans, [tex]\frac{5}{8}[/tex] pounds of gumballs and [tex]\frac{11}{4}[/tex] pounds of chocolate.

Step 2:

We add all the values to determine the total candy bought.

[tex]\frac{3}{2} +\frac{5}{8} + \frac{11}{4} = \frac{(4(3)+1(5)+2(11))}{8} .[/tex]

[tex]\frac{(4(3)+1(5)+2(11))}{8} = \frac{39}{8} .[/tex]

[tex]\frac{39}{8}[/tex] can also be written as [tex]4\frac{7}{8}[/tex].

So Jerome bought [tex]4\frac{7}{8}[/tex] pounds of candy which is option C.