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A 2.00-g particle moving at 8.80 m/s makes a perfectly elastic head-on collision with a resting 1.00-g object. (Assume the 2.00-g particle is moving in the positive direction before the collision. Indicate the direction with the sign of your answer.)

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pmdislamabad

Answer:

5.333 m/s

and

2.666 m/s

Explanation:

Let

m1 = 2.0g= 0.002kg

m2= 10 g =0.01 kg

V1i=initial velocity of m1 = 8 m/s

V2i=initial velocity of m2

V1f= final velocity of m1

V2f= final velocity of m2

Formula for this problem is ;

[tex]V1f=(\frac{m1-m2)}{m1+m2} )V1i[/tex]

and

[tex]V2f=(\frac{2m1}{m1+m2})V1i[/tex]

Putting values in above formulas we get;

V1f= -16/3 m/s = 5.333 m/s

V2f=8/3 m/s = 2.666 m/s

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