Respuesta :
Answer:
10.5 m/s²
Explanation:
Data:
The weight of the normal person = 850 N
Let the acceleration, the normal be = 9. 81 m/s²
Thus, the mass of the person can be calculated using the formula:
F = Ma
and
[tex]a = \frac{F}{m}[/tex]
where a = acceleration
F = Force
m = mass
therefore, a = [tex]\frac{850}{9.81} \\= 86.6 kg[/tex]
In the elevator, the person would be:
acceleration [tex]\frac{910}{86.6} \\= 10.5 m/s^{2}[/tex]
Answer:
0.692 m/s²
Explanation:
When an elevator is moving up the unbalance force is given as
ma = R-W............................ Equation 1
Where m = mass , a = acceleration of the elevator, R = weight when the elevator is moving up, W = normal weight
make a the subject of the equation
a = (R-W)/m...................... Equation 2
But,
W = mg.......................... Equation 3
Where g = acceleration due to gravity.
make m the subject of the equation
m = W/g..................... Equation 4
Substitute equation 4 into equation 2
a = (R-W)/(W/g)
a = g(R-W)/W.................... Equation 5
Given: R = 910 N, W = 850 N
Constant: g = 9.8 m/s²
Substitute into equation 5
a = 9.8(910-850)/850
a = 9.8(60)/850
a = 588/850
a = 0.692 m/s²