Respuesta :

Answer:

10.5 m/s²

Explanation:

Data:

The weight of the normal person = 850 N

Let the acceleration, the normal be = 9. 81 m/s²

Thus, the mass of the person can be calculated using the formula:

F = Ma

and

[tex]a = \frac{F}{m}[/tex]

where a = acceleration

F = Force

m = mass

therefore, a = [tex]\frac{850}{9.81} \\= 86.6 kg[/tex]

In the elevator, the person would be:

acceleration [tex]\frac{910}{86.6} \\= 10.5 m/s^{2}[/tex]

Answer:

0.692 m/s²

Explanation:

When an elevator is moving up the unbalance force is given as

ma = R-W............................ Equation 1

Where m = mass , a = acceleration of the elevator, R = weight when the elevator is moving up, W = normal weight

make a the subject of the equation

a = (R-W)/m...................... Equation 2

But,

W = mg.......................... Equation 3

Where g = acceleration due to gravity.

make m the subject  of the equation

m = W/g..................... Equation 4

Substitute equation 4 into equation 2

a = (R-W)/(W/g)

a = g(R-W)/W.................... Equation 5

Given: R = 910 N, W = 850 N

Constant: g = 9.8 m/s²

Substitute into equation 5

a = 9.8(910-850)/850

a = 9.8(60)/850

a = 588/850

a = 0.692 m/s²