Answer:
(-3,3).
Step-by-step explanation:
The given points are (-6,-3) and (-1,7).
We need to find the coordinates of the point, which divides the line segment in 3:2.
Section formula: If a point divides a line in m:n, then the coordinates of point are
[tex]\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)[/tex]
Using this formula, we get
[tex]\left(\dfrac{3(-1)+2(-6)}{3+2},\dfrac{3(7)+2(-3)}{3+2}\right)[/tex]
[tex]\left(\dfrac{-3-12}{5},\dfrac{21-6}{5}\right)[/tex]
[tex]\left(\dfrac{-15}{5},\dfrac{15}{5}\right)[/tex]
[tex]\left(-3,3\right)[/tex]
Therefore, the coordinates of required point are (-3,3).
