Answer:
The other zero is also a rational number.
Step-by-step explanation:
In a quadratic equation
[tex]ax^2+bx+c=0[/tex]
Quadratic formula:
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Case 1: If [tex]b^2-4ac>0[/tex], then the given quadratic equation has two distinct real zeros.
Case 2: If [tex]b^2-4ac=0[/tex], then the given quadratic equation has exactly one real zero.
Case 3: If [tex]b^2-4ac<0[/tex], then the given quadratic equation has two distinct complex zeros.
It is given that the quadratic has 2 distinct zeros. One of the zeros is rational.
It means
[tex]b^2-4ac>0[/tex] and [tex]\sqrt{b^2-4ac}[/tex] is a rational number.
Therefore, the other zero is also a rational number.
