Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below: a.) P(s) + 3/2 Cl2(g) PCl3(g) Ka b.) PCl3(g) + Cl2(g) PCl5(g) Kb

Respuesta :

Answer: The equilibrium constant for the overall reaction is [tex]K_a\times K_b[/tex]

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) [tex]P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)[/tex]

[tex]K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}[/tex]

b) [tex]PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)[/tex]

[tex]K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}[/tex]

For overall reaction on adding a and b we get c

c) [tex]P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)[/tex]

[tex]K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}[/tex]

[tex]K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}[/tex]

The equilibrium constant for the overall reaction is [tex]K_a\times K_b[/tex]