Answer:
The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.
Step-by-step explanation:
Sample size of 30 or larger, so we can use the normal distribution to find the confidence interval.
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.93}{2} = 0.035[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.035 = 0.965[/tex], so [tex]z = 1.81[/tex]
Now, find M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 1.81*\frac{28}{\sqrt{40}} = 8[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 71492 - 8 = 71484 km.
The upper end of the interval is the sample mean added to M. So it is 71492 + 8 = 71500 km.
The 93% confidence interval for the equatorial radius of Jupiter is between 71484 km and 71500 km.