Answer:
The temperature increase = 23.15 °C.
Explanation:
Given data:
Mass of silver = 27.9 g
Heat added = 155 j
How many degree temperature increase = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of silver is = 0.240 j/g.°C
Now we will put the values in formula.
155 j = 27.9 g × 0.240 j/g.°C × ΔT
155 j = 6.696 j/°C × ΔT
ΔT = 155 j /6.696 j/°C
ΔT = 23.15 °C
