Answer with Explanation:
We are given that
Time period,T=2.65 s
a.Distance between the equilibrium position and the point at maximum height is called amplitude.
Therefore, A=36 cm=[tex]\frac{36}{100}=0.36 m[/tex]
1 m=100 cm
b.Angular frequency,[tex]\omega=\frac{2\pi}{T}=\frac{2\pi}{2.65}=2.37 rad/s[/tex]
c.Maximum speed,[tex]v_{max}=A\omega[/tex]
Using the formula
Maximum speed,[tex]v_{max}=0.36\times 2.37=0.85 m/s[/tex]
