Answer:
30,240 ways
Step-by-step explanation:
If the order in which students are selected matters, than the number of possible groups that can be formed is given by the permutation of picking five out of 10 students:
[tex]n=\frac{10!}{(10-5)!}\\n=10*9*8*7*6\\n=30,240\ ways[/tex]
There are 30,240 possible groups that may be formed.
Answer:
30,240ways
Step-by-step explanation:
This is a permutation problem, we need to create five teams out of ten classes of students.
The formula for permutation is given below as;
P(n,r) = n!÷(n-r)!
Our n in this case is given as n=10
While our r is this question is given as r = 5
Now , substituting the value of n and r in to the formula, we have
P(10,5) = 10!÷(10-5)!
=10!÷5!
= (10×9×8×7×6×5×4×3×2×1)÷5×4×3×2×1
=10×9×8×7×6
=30,240ways
Therefore, the correct answer is 30,240ways
