2. ATO kg bouting ball would require what force to accelerate down an alleyway at a rate of ons?
F=
m=
a=
3. Salty has a car that accelerates at 5 m/s. If the car has a mass of 1000 kg, how much torbe
car produce?
F=
m=
a=
4. What is the mass of a falling rock if it produces a force of 147 N?
F=
m=
a=
5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at
a rate of 5 m/s?
F=
m=
a=​

need help cause this is due tmr

Respuesta :

Answer:

  • 2. 30N
  • 3. 5,000N
  • 4. 15 kg
  • 5. 2,800 kg

Explanation:

2. A 10 kg bowling  ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?

Notice that I completed the question with the garbled and missing values:

Data:

  • F = ?
  • m = 10 kg
  • a = 3m/s²

Physical principles:

  • Newton's second law: [tex]F=m\times a[/tex]

Solution:

  • Substitute and compute

        [tex]F=10kg\times 3m/s^2=30N[/tex]

3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?

Notice that I arranged the typos.

Data:

  • F = ?
  • m = ?
  • a = ?

Physical principles:

  • Newton's second law: [tex]F=m\times a[/tex]

Solution:

  • Substitute and compute

       [tex]F=1,000kg\times5m/s^2=5,000N[/tex]

4. What is the mass of a falling rock if it produces a force of 147 N?

Data:

  • F = 147N
  • m = ?
  • a = falling rock

Physical principles:

  • neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
  • Newton's second law: [tex]F=m\times a[/tex]

Solution:

  • Clear m from Newton's second law

         [tex]m=\dfrac{F}{a}[/tex]

  • Substitute with F = 147 N and a = g = 9.8m/s², and compute

      [tex]m=\dfrac{147N}{9.8m/s^2}=15Kg[/tex]

5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?

Data:

  • F= 14,000N
  • m = ?
  • a =​ 5m/s²

Physical principles:

  • Second Newton's law: [tex]F=m\times a[/tex]

Solution:

  • Clear m from Newton's second law

         [tex]m=\dfrac{F}{a}[/tex]

  • Substitute with F = 14,000 N and a = 5m/s², and compute

      [tex]m=\dfrac{14,000N}{5m/s^2}=2,800kg[/tex]