Can someone please help me solve this?

[tex]g(x)=cf(x), \ \ where \ c>1[/tex]
[tex]g(x)=f(x+k), \ \ \ where \ k>0[/tex]
Therefore, applying a vertical stretch by a factor of 3 followed by a translation 2 units left we have:
[tex]g(x)=3(2\sqrt{x+2}-1) \\ \\ \\ Distributive \ property: \\ \\ \boxed{g(x)=6\sqrt{x+2}-3}[/tex]