The answer for the following problem is explained below.
The specific heat of oil is 7.98 J/gram °C
Explanation:
Given:
heat (q)=878 J
mass of oil (m) =5 grams
initial temperature ([tex]t_{1}[/tex]) =34°C
final temperature ([tex]t_{2}[/tex]) = 56°C
To solve:
specific heat of the oil (c)
We know;
c =q÷(mΔT)
ΔT= ([tex]t_{2}[/tex]) - ([tex]t_{1}[/tex])
ΔT = 56°C - 34°C
ΔT = 22°C
c =[tex]\\ \frac{878}{5*22}[/tex]
c =878÷ 110
c =7.98 J/gram °C
Therefore the specific heat of oil is 7.98 J/gram °C
